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Proof step 34 from proof isarray-putbar (previous step)

okbytearray(r1, st), is_array(r, putByteArray(bytes0, r1, i + 1, st)), ∀ r, r1, i, st. is_array(r, putByteArray(bytes0, r1, i, st)) ∧ okbytearray(r1, st) → r = r1 ∨ is_array(r, st) ⊦ r = r1, is_array(r, st)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 3, [QUANTTERMLIST : (r, r1, i + 1, st)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, r1, i + 1, st)]]