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Proof step 16 from proof isarray-subset (previous step)

is_array(r, st), st ⊆ st1 ⊦ is_array(r, st1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_array(r, st) ↔ r ≠ jvmref ∧ r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ is_arraytype(st[r -- _type] .type) ∧ okarray(r, st[r -- _type] .type .type, st)
Proof step 15:
r ≠ jvmref ∧ r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ is_arraytype(st[r -- _type] .type) ∧ okarray(r, st[r -- _type] .type .type, st), st ⊆ st1 ⊦ is_array(r, st1)

Rule argument

[crewrite-arg: is-any-array, F, [st, r] → [st, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r)]]