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Proof step 12 from proof keys-put-in (previous step)

sk ∈ fis0, ∀ sk, val. sk ∈ fis0 → fis0[sk, val] .keys = fis0 .keys ⊦ sk = sk0, fis0[sk, val] .keys = fis0 .keys

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 2, [QUANTTERMLIST : (sk, val)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk, val)]]