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Proof step 12 from proof nonnullrefs-dups-key (previous step)

fis0[sk] = refval(r), fis0[sk0] = refval(r), sk ∈ fis0, sk0 ∈ fis0 ⊦ r1 = jvmref, r = jvmref, sk = sk0, sk = sk3, ((sk3 × refval(r1)) ' + fis0)[sk0] = refval(r), dups(fis0 .keys), sk3 ∈ fis0 .keys, ∃ r0, sk1, sk2. sk1 ≠ sk2 ∧ r0 ≠ jvmref ∧ ((sk3 × refval(r1)) ' + fis0)[sk1] = refval(r0) ∧ ((sk3 × refval(r1)) ' + fis0)[sk2] = refval(r0) ∧ (sk1 = sk3 ∨ sk1 ∈ fis0) ∧ (sk2 = sk3 ∨ sk2 ∈ fis0)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: assoclist instance-name: fieldinit lemma-name: assoc-no antecedent: succedent: sk ≠ sk0 → ((sk0 × val) ' + fis)[sk] = fis[sk] substlist: [sk, fis, val, sk0] → [sk0, fis0, refval(r1), sk3] add preconditions?: F is rewrite lemma?: T current spec?: F rotate lemma?: F replace all?: T paths: ((1, 0, 4)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : assoclist, fieldinit, assoc-yes, ⊦ ((sk × val) ' + fis)[sk] = val], [CSIMPNAMEDSEQ : list, fieldinit-assoclista, a, ⊦ (fis + fis0) + fis1 = fis + fis0 + fis1], [CSIMPNAMEDSEQ : javavalue, , inj-03, ⊦ refval(r) = refval(r0) ↔ r = r0])], [EXTRATERMS : (sk0, fis0, refval(r1), sk3)]]