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Proof step 36 from proof nonnullrefs-dups-key (previous step)

fis0[sk] = refval(r), fis0[sk0] = refval(r), sk ∈ fis0, sk0 ∈ fis0, ¬ is_referencevalue(val) ∨ val .refval = jvmref ⊦ r = jvmref, sk = sk0, dups(fis0 .keys), sk3 ∈ fis0 .keys, sk ≠ sk0 ∧ r ≠ jvmref ∧ ((sk3 × val) ' + fis0)[sk] = refval(r) ∧ ((sk3 × val) ' + fis0)[sk0] = refval(r) ∧ (sk = sk3 ∨ sk ∈ fis0) ∧ (sk0 = sk3 ∨ sk0 ∈ fis0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 35:
fis0[sk] = refval(r), fis0[sk0] = refval(r), sk ∈ fis0, sk0 ∈ fis0, ¬ is_referencevalue(val) ∨ val .refval = jvmref ⊦ r = jvmref, sk = sk0, dups(fis0 .keys), sk3 ∈ fis0 .keys, ((sk3 × val) ' + fis0)[sk] = refval(r) ∧ ((sk3 × val) ' + fis0)[sk0] = refval(r)

Rule argument

[emptyarg]

Additional information

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