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Proof step 13 from proof nonnullrefs-dups (previous step)

((sk1 × val) ' + fis0)[sk0] = refval(r), ((sk1 × val) ' + fis0)[sk] = refval(r), is_referencevalue(val), sk0 ∈ (sk1 × val) ' + fis0, sk ∈ (sk1 × val) ' + fis0, ∀ sk2, r0, sk3. fis0[sk2] = refval(r0) ∧ fis0[sk3] = refval(r0) ∧ sk2 ∈ fis0 ∧ sk3 ∈ fis0 → sk3 = sk2 ∨ r0 = jvmref ⊦ sk = sk0, r = jvmref, val .refval = jvmref, dups(fis0 .vals .nonnullrefs), val .refval ∈ fis0 .vals .nonnullrefs

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: javavalue instance-name: lemma-name: elim-13 antecedent: succedent: is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) substlist: [val, r] → [val, r1] add preconditions?: F is rewrite lemma?: F current spec?: F rotate lemma?: T replace all?: T paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (val, r1)]]