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Proof step 17 from proof nonnullrefs-dups (previous step)

fis0[sk0] = refval(r), fis0[sk] = refval(r), sk ∈ fis0, sk0 ∈ fis0, ¬ is_referencevalue(val) ∨ val .refval = jvmref, ∀ sk2, r0, sk3. fis0[sk2] = refval(r0) ∧ fis0[sk3] = refval(r0) ∧ sk2 ∈ fis0 ∧ sk3 ∈ fis0 → sk3 = sk2 ∨ r0 = jvmref ⊦ sk = sk0, r = jvmref, sk = sk1, sk0 = sk1, dups(fis0 .vals .nonnullrefs)

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 6, [extquanttermlist: (sk0, r, sk) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk0, r, sk)]]