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Proof step 28 from proof nonnullrefs-dups (conclusion)

⊦ fis[sk] = refval(r) ∧ fis[sk0] = refval(r) ∧ sk ≠ sk0 ∧ sk ∈ fis ∧ sk0 ∈ fis ∧ r ≠ jvmref → dups(fis .vals .nonnullrefs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
fis[sk0] = refval(r), fis[sk] = refval(r), sk0 ∈ fis, sk ∈ fis ⊦ sk = sk0, r = jvmref, dups(fis .vals .nonnullrefs)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]