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Proof step 10 from proof nonnullrefs-in (previous step)

fis0[sk] = refval(r), sk ∈ fis0, ∀ sk, r. fis0[sk] = refval(r) ∧ sk ∈ fis0 → r = jvmref ∨ r ∈ fis0 .vals .nonnullrefs ⊦ r = jvmref, sk = sk0, r ∈ (val ' + fis0 .vals) .nonnullrefs

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: valuesfuns instance-name: lemma-name: nonnullrefs-no antecedent: succedent: ¬ is_referencevalue(val) ∨ val .refval = jvmref → (val ' + vals) .nonnullrefs = vals .nonnullrefs substlist: [vals, val] → [fis0 .vals, val] add preconditions?: F is rewrite lemma?: T current spec?: F rotate lemma?: F replace all?: T paths: ((1, 0, 2, 1, 1)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (fis0 .vals, val)]]