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Proof step 13 from proof nonnullrefs-in (previous step)

fv = sk0 × val, (fv ' + fis0)[sk] = refval(r), sk ∈ fv ' + fis0, ∀ sk, r. fis0[sk] = refval(r) ∧ sk ∈ fis0 → r = jvmref ∨ r ∈ fis0 .vals .nonnullrefs ⊦ r = jvmref, r ∈ (val ' + fis0 .vals) .nonnullrefs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
((sk0 × val) ' + fis0)[sk] = refval(r), sk ∈ (sk0 × val) ' + fis0, ∀ sk, r. fis0[sk] = refval(r) ∧ sk ∈ fis0 → r = jvmref ∨ r ∈ fis0 .vals .nonnullrefs ⊦ r = jvmref, r ∈ (val ' + fis0 .vals) .nonnullrefs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]