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Proof step 6 from proof okarray-out (conclusion)

⊦ okarray(val, ty, i, st[_out, val0]) ↔ okarray(val, ty, i, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ refval(rk .ref) ≠ val → (okarray(val, ty, i, st[rk, val0]) ↔ okarray(val, ty, i, st))
Proof step 5:
¬ refval(_out .ref) ≠ val ⊦ okarray(val, ty, i, st[_out, val0]) ↔ okarray(val, ty, i, st)

Rule argument

[crewrite-arg: okarray-put-07 , F , [val0, rk, st, i, ty, val] → [val0, _out, st, i, ty, val] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (val0, _out, st, i, ty, val)]]