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Proof step 44 from proof okarray-put-07 (conclusion)

⊦ refval(rk .ref) ≠ val → (okarray(val, ty, i, st[rk, val0]) ↔ okarray(val, ty, i, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 43:
⊦ refval(rk .ref) = val, okarray(val, ty, i, st[rk, val0]) ↔ okarray(val, ty, i, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]