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Proof step 26 from proof okarray-substore (previous step)

st[r -- _length] = intval(i), st0[r -- _length] = intval(i), st0[r -- _type] = typeval(mkarraytype(ty0)), st[r -- _type] = typeval(mkarraytype(ty0)), j0 < i, r -- _length ∈ st0, r -- _type ∈ st, ty0 ≤ ty, r -- _length ∈ st, 0 ≤ i, r ∈ st, r -- _type ∈ st0, r ∈ st0, 0 ≤ j0, 0 < i, ¬ j < 0 ∧ ¬ i ≤ j → oktype(st[r -- j '], ty, st), ∀ j. ¬ j < 0 ∧ ¬ i ≤ j → oktype(st[r -- j '], ty, st), r -- j0 ' ∈ st → r -- j0 ' ∈ st0 ∧ st[r -- j0 '] = st0[r -- j0 '], ∀ rk. rk ∈ st → rk ∈ st0 ∧ st[rk] = st0[rk], ∀ j1. ¬ j1 < 0 ∧ ¬ i ≤ j1 → r -- j1 ' ∈ st ⊦ r = jvmref, r -- j0 ' ∈ st0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
st[r -- _length] = intval(i), st0[r -- _length] = intval(i), st0[r -- _type] = typeval(mkarraytype(ty0)), st[r -- _type] = typeval(mkarraytype(ty0)), j0 < i, r -- _length ∈ st0, r -- _type ∈ st, ty0 ≤ ty, r -- _length ∈ st, 0 ≤ i, r ∈ st, r -- _type ∈ st0, r ∈ st0, 0 ≤ j0, 0 < i, ∀ rk. rk ∈ st → rk ∈ st0 ∧ st[rk] = st0[rk], ∀ j1. ¬ j1 < 0 ∧ ¬ i ≤ j1 → r -- j1 ' ∈ st, ¬ j < 0 ∧ ¬ i ≤ j → oktype(st[r -- j '], ty, st), ∀ j. ¬ j < 0 ∧ ¬ i ≤ j → oktype(st[r -- j '], ty, st) ⊦ r = jvmref, r -- j0 ' ∈ st0, r -- j0 ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]