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Proof step 2 from proof okarray-union-04 (previous step)

okarray(val, ty, i, st0) ⊦ okarray(val, ty, i, st ∪ st0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ okarray(val, ty, i, st) ∧ st ⊆ st0 → okarray(val, ty, i, st0)

Rule argument

[crewrite-arg: okarray-subset , F , [val, ty, i, st, st0] → [val, ty, i, st0, st ∪ st0] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ st0 ⊆ st ∪ st0])], [EXTRATERMS : (val, ty, i, st0, st ∪ st0)]]