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Proof step 33 from proof okarray-union (conclusion)

⊦ ¬ r ∈ st .refs → (okarray(refval(r), ty, i, st ∪ st0) ↔ okarray(refval(r), ty, i, st0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
⊦ okarray(refval(r), ty, i, st ∪ st0) ↔ okarray(refval(r), ty, i, st0), r ∈ st .refs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]