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Proof step 5 from proof okarray-update (previous step)

refval((r0 -- sk) .ref) ≠ refval(r), ∀ r, r0, ty, i, st. r = r0 ∨ (okarray(refval(r), ty, i, update(r0, fis0, st)) ↔ okarray(refval(r), ty, i, st)) ⊦ r = r0, okarray(refval(r), ty, i, update(r0, fis0, st)) ↔ okarray(refval(r), ty, i, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ r, r0, ty, i, st. r = r0 ∨ (okarray(refval(r), ty, i, update(r0, fis0, st)) ↔ okarray(refval(r), ty, i, st)) ⊦ r = r0, okarray(refval(r), ty, i, update(r0, fis0, st)) ↔ okarray(refval(r), ty, i, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ refval(r) = refval(r0) ↔ r = r0], [CSIMPSEQ : ⊦ (r -- sk) .ref = r])]]