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Proof step 18 from proof okarrays-all (previous step)

okarrays(r, fis0, st) ↔ (∀ sk, val. sk × val ∈ fis0 → is_integervalue(val) ∧ is_fskey(sk) ∧ is_arraytype(sk .fs .type) ∧ okarray(st[r -- sk], sk .fs .type .type, val .intval, st)) ⊦ okarrays(r, (sk × val) ' + fis0, st) ↔ (∀ sk0, val0. sk0 × val0 = sk × val ∨ sk0 × val0 ∈ fis0 → is_integervalue(val0) ∧ ¬ is_indexkey(sk0) ∧ is_arraytype(sk0 .fs .type) ∧ okarray(st[r -- sk0], sk0 .fs .type .type, val0 .intval, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
okarrays(r, fis0, st) ↔ (∀ sk, val. sk × val ∈ fis0 → is_integervalue(val) ∧ is_fskey(sk) ∧ is_arraytype(sk .fs .type) ∧ okarray(st[r -- sk], sk .fs .type .type, val .intval, st)) ⊦ okarrays(r, (sk × val) ' + fis0, st) ↔ (∀ sk0, val0. sk0 × val0 ∈ fis0 ∨ sk0 = sk ∧ val0 = val → is_integervalue(val0) ∧ ¬ is_indexkey(sk0) ∧ is_arraytype(sk0 .fs .type) ∧ okarray(st[r -- sk0], sk0 .fs .type .type, val0 .intval, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ sk × val = sk0 × val0 ↔ sk = sk0 ∧ val = val0])]]