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Proof step 15 from proof okclass-03 (previous step)

⊦ sk = _type, reftypep(val, st[r0 -- sk, val0]) ∧ (val .refval ≠ jvmref → val .refval -- _type ∈ st[r0 -- sk, val0] ∧ st[val .refval -- _type] = typeval(mkclasstype(class1))) ↔ okclass(val, class1, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ okclass(val, class1, st) ↔ reftypep(val, st) ∧ (val .refval ≠ jvmref → val .refval -- _type ∈ st ∧ st[val .refval -- _type] = typeval(mkclasstype(class1)))
Proof step 14:
⊦ sk = _type, reftypep(val, st[r0 -- sk, val0]) ∧ (val .refval ≠ jvmref → val .refval -- _type ∈ st[r0 -- sk, val0] ∧ st[val .refval -- _type] = typeval(mkclasstype(class1))) ↔ reftypep(val, st) ∧ (val .refval ≠ jvmref → val .refval -- _type ∈ st ∧ st[val .refval -- _type] = typeval(mkclasstype(class1)))

Rule argument

[crewrite-arg: okclass, F, [st, class1, val] → [st, class1, val]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, class1, val)]]