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Proof step 9 from proof okclass-03 (previous step)

val = refval(r), is_referencevalue(val) ⊦ sk = _type, (r = jvmref ∨ r ∈ st[r0 -- sk, val0]) ∧ (r ≠ jvmref → r -- _type ∈ st[r0 -- sk, val0] ∧ st[r -- _type] = typeval(mkclasstype(class1))) ↔ (r = jvmref ∨ r ∈ st) ∧ (r ≠ jvmref → r -- _type ∈ st ∧ st[r -- _type] = typeval(mkclasstype(class1)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
⊦ sk = _type, (r = jvmref ∨ r ∈ st[r0 -- sk, val0]) ∧ (r ≠ jvmref → r -- _type ∈ st[r0 -- sk, val0] ∧ st[r -- _type] = typeval(mkclasstype(class1))) ↔ (r = jvmref ∨ r ∈ st) ∧ (r ≠ jvmref → r -- _type ∈ st ∧ st[r -- _type] = typeval(mkclasstype(class1)))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]