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Proof step 4 from proof okclass-out (conclusion)

⊦ okclass(val, class1, st[_out, val0]) ↔ okclass(val, class1, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ okclass(val, class1, st) ↔ reftypep(val, st) ∧ (val .refval ≠ jvmref → val .refval -- _type ∈ st ∧ st[val .refval -- _type] = typeval(mkclasstype(class1)))
Proof step 3:
reftypep(val, st), val .refval ≠ jvmref → val .refval -- _type ∈ st ∧ st[val .refval -- _type] = typeval(mkclasstype(class1)) ⊦ okclass(val, class1, st[_out, val0])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (st[_out, val][r -- _type]) = st[r -- _type]], [CSIMPSEQ : ⊦ r -- _type ∈ st[_out, val] ↔ r -- _type ∈ st], [CSIMPSEQ : ⊦ reftypep(val, st[_out, val0]) ↔ reftypep(val, st)])]]