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Proof step 22 from proof okstore-03 (previous step)

is_typevalue((_type = sk ⊃ val; st[r -- _type])), _mode ∈ st, _out ∈ st, r -- _type ∈ st ∨ _type = sk, ∀ r. r ≠ jvmref ∧ r ∈ st → r -- _type ∈ st ∧ is_typevalue(st[r -- _type]), r0 = r ∨ r0 ∈ st ⊦ r = jvmref, r0 = jvmref, (r0 = r ∧ _type = sk ∨ r0 -- _type ∈ st) ∧ is_typevalue(((r0 = r ∧ _type = sk) ⊃ val; st[r0 -- _type]))

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

[CASEDARG : pos: right 3, ()]

Additional information

[[CONCRETESIMPRULES : ()]]