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Proof step 46 from proof subset-okarray (conclusion)

⊦ st ⊆ st0 ∧ okarray(r, ty, st) → okarray(r, ty, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ okarray(r, ty, st) → r ≠ jvmref ∧ r ∈ st
Proof step 45:
st ⊆ st0, okarray(r, ty, st), r ∈ st ⊦ r = jvmref, okarray(r, ty, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]