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Proof step 8 from proof update-at-notin (conclusion)
⊦ ¬ sk ∈ fis → (update(r, fis, st)[r0 -- sk]) = st[r0 -- sk]
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 7
:
⊦ (update(r, fis, st)[r0 -- sk]) = st[r0 -- sk], sk ∈ fis
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]