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Proof step 3 from proof update-at (previous step)

∀ r, r0, st, sk. r = r0 ∨ (update(r0, fis0, st)[r -- sk]) = st[r -- sk] ⊦ r = r0, (update(r0, fis0, st)[r -- sk]) = st[r -- sk]

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 1, [QUANTTERMLIST : (r, r0, st, sk)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, r0, st, sk)]]