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Proof step 2 from proof update-in-02 (conclusion)
⊦ r ∈ st → r ∈ update(r0, fis, st)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 1
:
⊦ r ∈ update(r0, fis, st) ↔ r ∈ st ∨ r = r0 ∧ fis ≠ []
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]