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Proof step 13 from proof update-in-03 (conclusion)

⊦ r ∈ update(r0, fis, st) ↔ r ∈ st ∨ r = r0 ∧ fis ≠ []

User applied rule structural induction

And obtained the following new goals

Proof step 1:
⊦ update(r, [], st) = st
Proof step 12:
∀ r, r0, st. r ∈ update(r0, fis0, st) ↔ r ∈ st ∨ r = r0 ∧ fis0 ≠ [] ⊦ r ∈ update(r0, fv + fis0, st) ↔ r ∈ st ∨ r = r0 ∧ fv + fis0 ≠ []

Rule argument

[VARWITHVARSEQSARG : fis, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : fieldinits generated by [], +;])]]