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Proof step 3 from proof update-rec-02 (conclusion)

⊦ fis ≠ [] → update(r, fis, st) = (update(r, fis .rest, st)[r -- fis .first .1, fis .first .2])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ fis = [], update(r, fis, st) = (update(r, fis .rest, st)[r -- fis .first .1, fis .first .2])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]