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Proof step 4 from proof update-refs (previous step)

∀ r, st. r ∈ st → update(r, fis0, st) .refs = st .refs, r ∈ st ⊦ update(r, fv + fis0, st) .refs = st .refs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ update(r, fv ' + fis, st) = (update(r, fis, st)[r -- fv .1, fv .2])
Proof step 3:
r ∈ st, ∀ r, st. r ∈ st → update(r, fis0, st) .refs = st .refs ⊦ update(r, fis0, st) .refs ++ r = st .refs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (r -- sk) .ref = r], [CSIMPSEQ : ⊦ st[rk, val] .refs = st .refs ++ rk .ref], [CSIMPSEQ : ⊦ (fis + fis0) + fis1 = fis + fis0 + fis1], [CSIMPSEQ : ⊦ fv + fis = fv ' + fis])]]