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Proof step 11 from proof validFields-putfis (previous step)

unique_al(fis), sk ∈ fis .keys ∨ sk = sk → r -- sk ∈ st, ∀ sk0. sk0 ∈ fis .keys → r -- sk0 ∈ st ⊦ _length = sk, _type = sk, _length ∈ fis, _type ∈ fis, hasKeys(r, fis .keys, st) ∧ r -- sk ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ sk ∈ fis .keys ↔ sk ∈ fis
Proof step 10:
unique_al(fis), sk ∈ fis ∨ sk = sk → r -- sk ∈ st, ∀ sk0. sk0 ∈ fis .keys → r -- sk0 ∈ st ⊦ _length = sk, _type = sk, _length ∈ fis, _type ∈ fis, hasKeys(r, fis .keys, st) ∧ r -- sk ∈ st

Rule argument

[crewrite-arg: keys-in, F, [fis, sk] → [fis, sk]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (fis, sk)]]