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Proof step 13 from proof validFields-putfis (previous step)

∀ sk0. sk0 ∈ fis[sk, val] .keys → r -- sk0 ∈ st, unique_al(fis) ⊦ _length = sk, _type = sk, _length ∈ fis, _type ∈ fis, hasKeys(r, fis .keys, st) ∧ r -- sk ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ sk0 ∈ fis[sk, val] .keys ↔ sk0 ∈ fis .keys ∨ sk0 = sk
Proof step 12:
unique_al(fis), ∀ sk0. sk0 ∈ fis .keys ∨ sk0 = sk → r -- sk0 ∈ st ⊦ _length = sk, _type = sk, _length ∈ fis, _type ∈ fis, hasKeys(r, fis .keys, st) ∧ r -- sk ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]