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Proof step 15 from proof validFields-putfis (previous step)

_type ≠ sk ∧ _length ≠ sk ∧ hasKeys(r, fis[sk, val] .keys, st), unique_al(fis) ⊦ hasKeys(r, fis .keys, st) ∧ sk ≠ _length ∧ sk ≠ _type ∧ r -- sk ∈ st, _length ∈ fis, _type ∈ fis

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
hasKeys(r, fis[sk, val] .keys, st), unique_al(fis) ⊦ _length = sk, _type = sk, _length ∈ fis, _type ∈ fis, hasKeys(r, fis .keys, st) ∧ r -- sk ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]