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Proof step 23 from proof validFields-putfis (previous step)

r ∈ st, unique_al(fis), r -- sk ∈ st, ∀ sk. sk ∈ fis .keys → r -- sk ∈ st, sk0 ∈ fis ⊦ sk = _length, sk = _type, r -- sk0 ∈ st, _type ∈ fis, _length ∈ fis

User applied rule all left

And obtained the following new goals

Proof step 22:
r ∈ st, unique_al(fis), r -- sk ∈ st, sk0 ∈ fis .keys → r -- sk0 ∈ st, ∀ sk. sk ∈ fis .keys → r -- sk ∈ st, sk0 ∈ fis ⊦ sk = _length, sk = _type, r -- sk0 ∈ st, _type ∈ fis, _length ∈ fis

Rule argument

[EXRARG : pos: left 4, [extquanttermlist: (sk0)abort:F, discard:F, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk0)]]