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Proof step 25 from proof validFields-putfis (previous step)

r ∈ st, unique_al(fis), r -- sk ∈ st, hasKeys(r, fis .keys, st), sk0 = sk ∨ sk0 ∈ fis ⊦ sk = _length, sk = _type, r -- sk0 ∈ st, _type ∈ fis, _length ∈ fis

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
r ∈ st, unique_al(fis), r -- sk ∈ st, hasKeys(r, fis .keys, st), sk0 ∈ fis ⊦ sk = _length, sk = _type, r -- sk0 ∈ st, _type ∈ fis, _length ∈ fis

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]