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Proof step 3 from proof vals-at (previous step)

fis0[m] = sk × val, m < # fis0, ∀ n, sk0, val0. fis0[n] = sk0 × val0 ∧ ¬ # fis0 ≤ n → (fis0 .vals)[n] = val0 ⊦ (fis0 .vals)[m] = val, fis0 = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 3, [QUANTTERMLIST : (m, sk, val)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : nat, , ls-le-simp, ⊦ m < n → (n ≤ m ↔ false)])], [EXTRATERMS : (m, sk, val)]]