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Proof step 117 from proof cyclic-pseq (previous step)

st1[r1 -- _type] .type = mkclasstype(class), st[r2 -- _type] = st1[r1 -- _type], ps=(st[r2 -- fs '] .refval, st, st1[r1 -- fs '] .refval, st1), validrefs(str, (st[r2 -- fs '] .refval ' + refs) + r0 ', fs .type, st), is_obj(str, r2, st), is_obj(str, r1, st1), fs ' ∈ instfields(class), is_referencevalue(st[r2 -- fs ']), ∀ fs. fs ' ∈ instfields(class) ∧ ¬ is_referencevalue(st[r2 -- fs ']) → st[r2 -- fs '] = st1[r1 -- fs '], junkref(str, st[r2 -- fs '] .refval, st) ∨ junkref(str, st1[r1 -- fs '] .refval, st1) ∨ cyclic(str, st1[r1 -- fs '] .refval, st1), ∀ st, r, st0, r0, str0. maxpath(str0, r0, st0) < maxpath(str, r1, st1) → (ps=(r, st, r0, st0) ∧ cyclic(str0, r, st) → junkref(str0, r, st) ∨ junkref(str0, r0, st0) ∨ cyclic(str0, r0, st0)) ⊦ r2 = st[r2 -- fs '] .refval, r2 = jvmref, r1 = jvmref, st[r2 -- fs '] .refval ∈ refs, dups(refs), r2 ∈ refs, cyclic(str, r1, st1), junkref(str, r2, st), r0 ≠ r2 ∧ r0 ≠ st[r2 -- fs '] .refval ∧ ¬ r0 ∈ refs, is_referencevalue(st1[r1 -- fs ']) ∧ st1[r1 -- fs '] .refval ≠ jvmref ∧ (¬ st1[st1[r1 -- fs '] .refval -- _type] .type ≤ fs .type ∨ junkref(str, st1[r1 -- fs '] .refval, st1))

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[speclemmaarg: , ¬ is_referencevalue(st[r -- fs ']) ∧ is_reftype(fs .type) ∧ fs ' ∈ instfields(class) ∧ st[r -- _type] .type = mkclasstype(class) → ¬ is_obj(str, r, st) ,[st, r, fs, class, str] → [st1, r1, fs, class, str] ,F ,addfuns , ,is_obj-field-norefval ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st1, r1, fs, class, str)]]