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Proof step 159 from proof cyclic-pseq (previous step)

st[r2 -- _type] = st1[r1 -- _type], st[r2 -- _length] .intval = st1[r1 -- _length] .intval, r2 = st[r2 -- i '] .refval, 0 ≤ i, 0 < st1[r1 -- _length] .intval, ps=(r2, st, st1[r1 -- i '] .refval, st1), is_arraytype(st1[r1 -- _type] .type), is_array(str, r2, st), is_array(str, r1, st1), i < st1[r1 -- _length] .intval, is_referencevalue(st[r2 -- i ']), validrefs(str, r2 ', st1[r1 -- _type] .type .type, st), ∀ i. ¬ i < 0 ∧ ¬ st1[r1 -- _length] .intval ≤ i ∧ ¬ is_referencevalue(st[r2 -- i ']) → st[r2 -- i '] = st1[r1 -- i '], ∀ st, r, st0, r0, str0. maxpath(str0, r0, st0) < maxpath(str, r1, st1) → (ps=(r, st, r0, st0) ∧ cyclic(str0, r, st) → junkref(str0, r, st) ∨ junkref(str0, r0, st0) ∨ cyclic(str0, r0, st0)) ⊦ r2 = jvmref, r1 = jvmref, cyclic(str, r1, st1), junkref(str, r1, st1), junkref(str, r2, st), ∃ i0. ¬ i0 < 0 ∧ ¬ st1[r1 -- _length] .intval ≤ i0 ∧ is_referencevalue(st[r2 -- i0 ']) ∧ r2 = st[r2 -- i0 '] .refval

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

[EXRARG : pos: right 6, [QUANTTERMLIST : (i)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i ≤ j → (¬ ¬ j < i ↔ false)], [CSIMPSEQ : ⊦ i < j → (¬ ¬ j ≤ i ↔ false)])], [EXTRATERMS : (i)]]