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Proof step 194 from proof cyclic-pseq (previous step)

st[r2 -- _type] = st1[r1 -- _type], st[r2 -- _length] .intval = st1[r1 -- _length] .intval, (refs0 + r0 ') .first = st[r2 -- i '] .refval, ps=((refs0 + r0 ') .first, st, st1[r1 -- i '] .refval, st1), is_arraytype(st1[r1 -- _type] .type), is_array(str, r2, st), is_array(str, r1, st1), i < st1[r1 -- _length] .intval, is_referencevalue(st[r2 -- i ']), validrefs(str, refs0 + r0 ', st1[r1 -- _type] .type .type, st), 0 ≤ i, 0 < st1[r1 -- _length] .intval, ∀ i. ¬ i < 0 ∧ ¬ st1[r1 -- _length] .intval ≤ i ∧ ¬ is_referencevalue(st[r2 -- i ']) → st[r2 -- i '] = st1[r1 -- i '], ∀ st, r, st0, r0, str0. maxpath(str0, r0, st0) < maxpath(str, r1, st1) → (ps=(r, st, r0, st0) ∧ cyclic(str0, r, st) → junkref(str0, r, st) ∨ junkref(str0, r0, st0) ∨ cyclic(str0, r0, st0)) ⊦ refs0 = [], r2 = jvmref, r1 = jvmref, cyclic(str, r1, st1), junkref(str, r1, st1), junkref(str, r2, st), dups(refs0), r2 ∈ refs0, cyclic(str, (refs0 + r0 ') .first, st), r0 ≠ r2 ∧ ¬ r0 ∈ refs0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 193:
st[r2 -- _type] = st1[r1 -- _type], st[r2 -- _length] .intval = st1[r1 -- _length] .intval, refs0 .first = st[r2 -- i '] .refval, is_arraytype(st1[r1 -- _type] .type), is_array(str, r2, st), is_array(str, r1, st1), i < st1[r1 -- _length] .intval, is_referencevalue(st[r2 -- i ']), validrefs(str, refs0 + r0 ', st1[r1 -- _type] .type .type, st), 0 ≤ i, 0 < st1[r1 -- _length] .intval, ps=(refs0 .first, st, st1[r1 -- i '] .refval, st1), ∀ i. ¬ i < 0 ∧ ¬ st1[r1 -- _length] .intval ≤ i ∧ ¬ is_referencevalue(st[r2 -- i ']) → st[r2 -- i '] = st1[r1 -- i '], ∀ st, r, st0, r0, str0. maxpath(str0, r0, st0) < maxpath(str, r1, st1) → (ps=(r, st, r0, st0) ∧ cyclic(str0, r, st) → junkref(str0, r, st) ∨ junkref(str0, r0, st0) ∨ cyclic(str0, r0, st0)) ⊦ refs0 = [], r2 = jvmref, r1 = jvmref, cyclic(str, r1, st1), junkref(str, r1, st1), junkref(str, r2, st), dups(refs0), r2 ∈ refs0, cyclic(str, refs0 .first, st), r0 ≠ r2 ∧ ¬ r0 ∈ refs0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ refs ≠ [] → (refs + refs0) .first = refs .first])]]