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Proof step 11 from proof maxpath-array (previous step)

st[r -- i '] = refval(r0), maxpath(str, r, st) = 1 + # refs0, maxpath(str, r0, st) = 1 + # refs1, r ' + r0 ' + refs1 ∈ validrefset(str, r, st), is_valid_ref(str, r0, st), maxpath(str, r, st) ≤ maxpath(str, r0, st), 0 ≤ i, i < st[r -- _length] .intval, is_array(str, r, st), # refs0 ≤ # refs1, validrefs(str, r ' + refs0, st[r -- _type] .type, st), 0 < st[r -- _length] .intval, validrefs(str, r0 ' + refs1, st[r0 -- _type] .type, st), 2 + # refs1 ≤ maxpath(str, r, st), 2 + # refs1 ≤ maxpath(str, r0, st) ⊦ # validrefset(str, r0, st) = 0, validrefset(str, r0, st) = ∅, # validrefset(str, r, st) = 0, validrefset(str, r, st) = ∅, junkref(str, r, st), cyclic(str, r, st), dups(refs0), r ∈ refs0, has_reffield((r ' + refs0) .last, st), has_reffield((r0 ' + refs1) .last, st), dups(refs1), r0 ∈ refs1

User applied rule insert equation

And closed the goal!

Rule argument

[inserteqarg: pos: left 3,F,T,()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : n0 < n ⊦ m + ((* n)) ≤ m0 + ((* n0)) ↔ m + (n - n0) ≤ m0], [CSIMPSEQ : ⊦ m + m0 ≤ m ↔ m0 = 0], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m])]]