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Proof step 38 from proof maxpath-array (previous step)

st[r -- i '] = refval(refs .first), maxpath(str, r, st) = 1 + # refs0, maxpath(str, refs .first, st) = # refs, maxpath(str, r, st) ≤ # refs, 0 ≤ i, i < st[r -- _length] .intval, is_array(str, r, st), # refs0 < # refs, validrefs(str, r ' + refs0, st[r -- _type] .type, st), 0 < st[r -- _length] .intval, validrefs(str, refs, st[refs .first -- _type] .type, st), is_valid_ref(str, refs .first, st) ⊦ refs = [], # validrefset(str, refs .first, st) = 0, validrefset(str, refs .first, st) = ∅, # validrefset(str, r, st) = 0, validrefset(str, r, st) = ∅, has_reffield(refs .last, st), dups(refs), junkref(str, r, st), cyclic(str, r, st), dups(refs0), r ∈ refs0, has_reffield((r ' + refs0) .last, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [refs, r0, refs1] ,T ,list-data ,references-olista ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (refs, r0, refs1)]]