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Proof step 11 from proof pseq-subset-01 (previous step)

⊦ ¬ junkref(str, r, st) ∧ ¬ cyclic(str, r, st) ∧ ¬ junkref(str, r1, st1) ∧ ¬ cyclic(str, r1, st1) ∧ ps=(r, st, r1, st1) ∧ st ⊆ st2 → ps=(r, st2, r1, st1)

Lemma pseq-subset