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Proof step 17 from proof pseq-subset-01 (conclusion)

⊦ ¬ junkref(str, r, st) ∧ ¬ cyclic(str, r, st) ∧ ¬ junkref(str, r1, st1) ∧ ¬ cyclic(str, r1, st1) ∧ ps=(r, st, r1, st1) ∧ st1 ⊆ st2 → ps=(r, st, r1, st2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
st1 ⊆ st2, ps=(r, st, r1, st1) ⊦ junkref(str, r, st), cyclic(str, r, st), junkref(str, r1, st1), cyclic(str, r1, st1), ps=(r, st, r1, st2)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]