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Proof step 4 from proof pseq-subset-01 (previous step)

ps=(r1, st1, r, st), st1 ⊆ st2, cyclic(str, r1, st2) ⊦ cyclic(str, r, st), cyclic(str, r1, st1), junkref(str, r, st), junkref(str, r1, st1), ps=(r, st, r1, st2), junkref(str, r1, st2)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[speclemmaarg: , ¬ cyclic(str, r, st) ∧ st ⊆ st0 ∧ ¬ junkref(str, r, st) → ¬ cyclic(str, r, st0) ,[str, r, st, st0] → [str, r1, st1, st2] ,F ,compatible , ,cyclic-subset ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (str, r1, st1, st2)]]