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Proof step 7 from proof pseq-subset-01 (previous step)

junkref(str, r1, st2), ps=(r1, st1, r, st), st1 ⊆ st2 ⊦ cyclic(str, r, st), cyclic(str, r1, st1), junkref(str, r, st), junkref(str, r1, st1), ps=(r, st, r1, st2)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[speclemmaarg: ,¬ junkref(str, r, st) ∧ st ⊆ st1 → ¬ junkref(str, r, st1) ,[str, r, st, st1] → [str, r1, st1, st2] ,F ,compatible , ,junkref-subset ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (str, r1, st1, st2)]]