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Proof step 172 from proof pseq-subset (previous step)

st2[r -- _length] .intval = st1[r1 -- _length] .intval, st[r -- _length] .intval = st1[r1 -- _length] .intval, st2[r -- _type] = st1[r1 -- _type], st[r -- _type] = st1[r1 -- _type], is_referencevalue(st[r -- i ']), i < st1[r1 -- _length] .intval, is_referencevalue(st2[r -- i ']), is_array(str, r, st), is_array(str, r1, st1), r -- _type ∈ st, r -- _type ∈ st2, r ∈ st, r ∈ st2, is_arraytype(st1[r1 -- _type] .type), 0 ≤ i, 0 < st1[r1 -- _length] .intval, ps=(st[r -- i '] .refval, st, st1[r1 -- i '] .refval, st1), ∀ i. ¬ i < 0 ∧ ¬ st1[r1 -- _length] .intval ≤ i ∧ ¬ is_referencevalue(st[r -- i ']) → st[r -- i '] = st1[r1 -- i '], ∀ i. ¬ i < 0 ∧ ¬ st1[r1 -- _length] .intval ≤ i ∧ is_referencevalue(st[r -- i ']) → ps=(st[r -- i '] .refval, st, st1[r1 -- i '] .refval, st1), ∀ rk. rk ∈ st → rk ∈ st2 ∧ st[rk] = st2[rk], ∀ st1, r1, st2, st0, r0, str0. maxpath(str0, r0, st0) < maxpath(str, r, st) → ( st0 ⊆ st2 ∧ ps=(r0, st0, r1, st1) → junkref(str0, r0, st0) ∨ cyclic(str0, r0, st0) ∨ junkref(str0, r1, st1) ∨ cyclic(str0, r1, st1) ∨ ps=(r0, st2, r1, st1)) ⊦ r1 = jvmref, r = jvmref, ps=(st2[r -- i '] .refval, st2, st1[r1 -- i '] .refval, st1), cyclic(str, r1, st1), junkref(str, r1, st1), cyclic(str, r, st), junkref(str, r, st)

User applied rule all left

And obtained the following new goals

Rule argument

[EXRARG : pos: left 20, [extquanttermlist: (r -- i ')abort:F, discard:F, computed:F]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r -- i ')]]