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Proof step 185 from proof pseq-sym-01 (previous step)

st[r -- _type] = st1[r1 -- _type], st[r -- _length] .intval = st1[r1 -- _length] .intval, i0 < st1[r1 -- _length] .intval, is_arraytype(st1[r1 -- _type] .type), 0 ≤ i0, 0 < st1[r1 -- _length] .intval, is_referencevalue(st[r -- i0 ']), ps=(st[r -- i0 '] .refval, st, jvmref, st1), ∀ st, r, st0, r0, str0. maxpath(str0, r0, st0) < maxpath(str, r1, st1) → ( true → ( ¬ cyclic(str0, r, st) ∧ ¬ cyclic(str0, r0, st0) ∧ ¬ junkref(str0, r, st) ∧ ¬ junkref(str0, r0, st0) → (ps=(r, st, r0, st0) → ps=(r0, st0, r, st)))) ⊦ st1[r1 -- i0 '] = st[r -- i0 '], r1 = jvmref, r = jvmref, is_referencevalue(st1[r1 -- i0 ']), cyclic(str, r, st), cyclic(str, r1, st1), junkref(str, r, st), junkref(str, r1, st1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [st[r -- i0 '], r2] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (st[r -- i0 '], r2)]]