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Proof step 200 from proof pseq-sym-01 (previous step)

true, ∀ st, r, st0, r0, str0. maxpath(str0, r0, st0) < maxpath(str, r1, st1) → ( true → ( ¬ cyclic(str0, r, st) ∧ ¬ cyclic(str0, r0, st0) ∧ ¬ junkref(str0, r, st) ∧ ¬ junkref(str0, r0, st0) → (ps=(r, st, r0, st0) → ps=(r0, st0, r, st)))) ⊦ ¬ cyclic(str, r, st) ∧ ¬ cyclic(str, r1, st1) ∧ ¬ junkref(str, r, st) ∧ ¬ junkref(str, r1, st1) → (ps=(r, st, r1, st1) → ps=(r1, st1, r, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 199:
ps=(r, st, r1, st1), ∀ st, r, st0, r0, str0. maxpath(str0, r0, st0) < maxpath(str, r1, st1) → ( true → ( ¬ cyclic(str0, r, st) ∧ ¬ cyclic(str0, r0, st0) ∧ ¬ junkref(str0, r, st) ∧ ¬ junkref(str0, r0, st0) → (ps=(r, st, r0, st0) → ps=(r0, st0, r, st)))) ⊦ cyclic(str, r, st), cyclic(str, r1, st1), junkref(str, r, st), junkref(str, r1, st1), ps=(r1, st1, r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]