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Proof step 6 from proof pseq-sym (conclusion)

⊦ ¬ cyclic(str, r, st) ∧ ¬ cyclic(str, r1, st1) ∧ ¬ junkref(str, r, st) ∧ ¬ junkref(str, r1, st1) → (ps=(r, st, r1, st1) ↔ ps=(r1, st1, r, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ ps=(r, st, r1, st1) ↔ ps=(r1, st1, r, st), cyclic(str, r, st), cyclic(str, r1, st1), junkref(str, r, st), junkref(str, r1, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]