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Proof step 8 from proof unchNorec-validrefs-equiv (previous step)

¬ (validrefs(str, refs, ty, st) ∧ (∀ r. r ∈ refs → unchangedNorec(r, st, st0))), ∀ r. r ∈ refs → unchangedNorec(r, st, st0) ⊦ validrefs(str, refs, ty, st) ↔ validrefs(str, refs, ty, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
validrefs(str, refs, ty, st0), ∀ r. r ∈ refs → unchangedNorec(r, st, st0) ⊦ validrefs(str, refs, ty, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]