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Proof step 39 from proof unchNorec-validrefs-pathex (conclusion)

⊦ validrefs(str, refs, ty, st) ∧ r = refs .first ∧ r0 ∈ refs ∧ (∀ r. r ∈ refs → unchangedNorec(r, st, st0)) ∧ refs ≠ [] → path∃(str, r, r0, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
validrefs(str, refs, ty, st), r0 ∈ refs, ∀ r. r ∈ refs → unchangedNorec(r, st, st0) ⊦ refs = [], path∃(str, refs .first, r0, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]