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Proof step 13 from proof unchanged-cyclic (previous step)

∃ refs. dups(refs) ∧ refs .first = r ∧ validrefs(str, refs, st[r -- _type] .type, st), unchanged(str, r, st, st0) ⊦ junkref(str, r, st), ∃ refs. dups(refs) ∧ refs .first = r ∧ validrefs(str, refs, st0[refs .first -- _type] .type, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
dups(refs), validrefs(str, refs, st[refs .first -- _type] .type, st), unchanged(str, refs .first, st, st0) ⊦ junkref(str, refs .first, st), ∃ refs0. dups(refs0) ∧ refs0 .first = refs .first ∧ validrefs(str, refs0, st0[refs0 .first -- _type] .type, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]